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Two cells A and B each of 2V are connected in series to an external resistance R = 1 ohm. The internal resistance of A is r_(A)=1.9 ohm and B is r_(B)=00.9 ohm. Find the potential difference between the terminals of A. |
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Answer» SOLUTION :TOTAL current through the circuit `i=("voltage")/("Total resisance")` `=(4)/((1+1.9+0.9))=(4)/(3.8)A`  potential difference at A, `V_(A)=epsilon-ir =2-(4)/(3.8)xx1.9=2-2=0`. |
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