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two cars are traveling towards each other over a stretch of 575 km. car A starts at 10:00am and is going at a speed of 80kmph.car B starts at 11:00am and is traveling at 70kmph. when and where will they meet? |
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Answer» Let the duration CAR A traveled when they MEET be H hours. Therefore duration car B traveled when they meet will be (h-1) hours. Distance Car A would have traveled = Speed x times = 80 x h = 80h km Distance Car B would have traveled = Speed x times = 70 x (h - 1) = 70(h-1) km The total distance COVERED is 575km: 80h + 70(h - 1) = 575 km 80h + 70h - 70 = 575 150h = 645 h = 4.3 hours = 4 hours 18 mins 10.00am + 4 hours 18 mins = 2.18pm Distance Car A traveled = 80 x h = 80 x 4.3 = 344km Answer: They will meet at 2.18pm at 344 km from the point Car A started. |
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