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Two capillary tubes of radiir and 4r and lengths l, 3l are fitted horizontally to the bottom of the vessel with pressure head p in parallel with each other. Calculate the radius of the single tube of same length l which can replace the two capillaries such that rate of flow is not affected. |
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Answer» SOLUTION :r = RADIUS of each capillary `V_1V_2` = rate of flow of liquids through two capillaries `l_1l_2` = lengths of capillaries Total rate of flow of liquid `V=V_1 + V_2` l= LENGTH of a single tube which can replace the two capillaries. `V=(pi pr^(4))/(8 ETAL) .........(ii)` Using (i) and (ii) `(pi pr^(4))/(8 etal)=(pi pr^(4))/(8 eta) [1/l_(1)+1/l_(2)]` `1/l=1/l_(1)+1/l_(2)` `l=(l_(1) l_(2))/(l_(1)+l_(2))` |
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