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Two capillary tubes of lengths in the ratio `2 : 1` and radii in the ratio `1 : 2` are connected in series. Assume the flow of the liquid through the tube is steady. Then, the ratio of pressure difference across the tubes isA. `1 : 8`B. `1 : 16`C. `32 : 1`D. `1 : 1` |
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Answer» Correct Answer - C We know that the pressure `p alpha (r^(4))/(l)` `"Let" l_(1)=2l, l_(2)=l and r_(1)=r, r_(2)=2r` `"Now", (p_(1))/(p_(2))=(r_(1)^(4))/(l_(1))xx(l_(2))/(r_(2)^(4))Rightarrow (p_(1))/(p_(2))=(r^(4))/(2l)xx(l)/((2r)^4)` `(p_(1))/(p_(2))=(1)/(2xx(2)^(4)) Rightarrow (p_(1))/(p_(2))=(1)/(32)` |
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