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Two capacitor c1 = 2μf and c2 = 4μf are connected in series and a potential difference (p.d) of 1200 v is applied across it the potential difference across 2μf will beA) 400 V B) 600 V C) 800 V D) 900 V |
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Answer» The correct option is C) 800 V. Total capacitance equivalent = 2 × 4/ (2 + 4) = 8/6 = 4/3 Q = CV Q = 1200 x 4/3 Q = 1600 V = q/V V = 1600/2 V = 800 |
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