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Two bulbs which consume powers `P_(1) " and P_(2)` are connected in series. The power consumed by the combination isA. `P_(1)+P_(2)`B. `sqrt(P_(1)P_(2)`C. `(P_(1)P_(2))/(P_(1)+P_(2))`D. `(2P_(1)P_(2))/(P_(1)+P_(2))` |
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Answer» Correct Answer - A For a series circuit, `R_(s)=R_(1)+R_(2)` `rArri^(2)R_(s)=i^(2)R_(1)+i^(2)R_(2)rArrP_(s)=P_(1)+P_(2)` |
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