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Two bulbs one of `200` volts, `60` watts & the other of `200` volts, `100` watts are connected in series to a `200` volts supply. The power consumed will beA. `37.5` wattB. `160` wattC. `62.5` wattD. `110` watt |
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Answer» Correct Answer - A `1/P=1/(P_(1))+1/(P_(2))` `P=(P_(1)P_(2))/(P_(1)+P_(2))=(300xx600)/900=200 W` |
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