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Two bulbs have ratings 100 W, 220 V and 60 W, 220 V. Which one has the greater resistance ? |
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Answer» Solution :Resistance of FIRST BULB `R_(1)=(V^(2))/(P)=(22cancel(theta)xx22cancel(theta))/(cancel(100))=484Omega.` Resistance of second bulb `R_(2)=(V^(2))/(P)=(220xx22cancel(theta))/(6cancel(theta))=(4840)/(6)=806.6Omega.` `THEREFORE` The bulb rated 60 W,220V has the greater resistance. |
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