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Two bodies of mass 150g and 200g are approaching each other.Both the bodies have the same speed of 3m/s.Find the total momentum of the system |
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Answer» ong>Answer: 0.30 Ns Step-by-step explanation: Mass of BODY A, ma = 150 G = 0.15 kg Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kg Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the BODIES are MOVING towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative. Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/s Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/sVelocity of B, vb = 3 m/s Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/sVelocity of B, vb = 3 m/sNow, total momentum of the system, Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/sVelocity of B, vb = 3 m/sNow, total momentum of the system,P = mava + mbvb Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/sVelocity of B, vb = 3 m/sNow, total momentum of the system,P = mava + mbvb=> P = (0.15)(-3) + (0.25)(3) Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/sVelocity of B, vb = 3 m/sNow, total momentum of the system,P = mava + mbvb=> P = (0.15)(-3) + (0.25)(3)=> P = -0.45 + 0.75 Mass of body A, ma = 150 g = 0.15 kgMass of body B, mb = 250 g = 0.25 kgBoth the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.Velocity of A, va = - 3 m/sVelocity of B, vb = 3 m/sNow, total momentum of the system,P = mava + mbvb=> P = (0.15)(-3) + (0.25)(3)=> P = -0.45 + 0.75=> P = 0.30 Ns Hope it helps you please mark me as the branliest answer |
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