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Two bodies are dropped at thesame time to fall freely fromthe height of 49m and 25mrespectively. Find the ratio betweenthe times taken by them toreach the earth's surface..... |
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Answer» For ANSWERING this problem, you may need to know the direct result for TIME of fall of an object It is t=2Hg−−−−√ Where symbols have their usual meaning You may also take out this result by putting v=2gH−−−−√ and u=0 in the first EQUATION of kinematics. So for 1ST object t1=2H1g−−−−√(1) And for 2ndobject t2=2H2g−−−−√(2) Dividing 1 by 2 t1t2=2H1g−−−−√2H2g−−−−√ HENCE t1t2=H1H2−−−√ |
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