Two blocks of masses M_(1) and M_(2) connected by a light spring rest on a horizontal plane . The coefficient of friction between the blocks and the surface is equal to mu . The minimum constant force that has to be applied in the horizontal direction to the block of mass M_(1) in order to shift the other block is (M_(1) + (M_(2))/(alpha)) mu g, then alphais :

Two blocks of masses M_(1) and M_(2) connected by a light spring rest

1.	Two blocks of masses M_(1) and M_(2) connected by a light spring rest on a horizontal plane . The coefficient of friction between the blocks and the surface is equal to mu . The minimum constant force that has to be applied in the horizontal direction to the block of mass M_(1) in order to shift the other block is (M_(1) + (M_(2))/(alpha)) mu g, then alphais :
Answer» SOLUTION : `F = MU M_(1) G + T "" ….(i)` `T = muM_(2) g "" …..(II)` By solving , we get `alpha`.