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Two block of masses `M_(1)` and, `M_(2)` are connected with a string which passed over a smooth pulley . The mass `M_(1)` is placed on a tough inclined plane as shown in figure .The coefficient of friction between and block and the inclined plane is `mu` what should be the minimum mass `M_(2)` so that the block `M_(1)` slides upwards?A. `(m_(1))/(m_(2)) = mu sin theta + cos theta`B. `(m_(1))/(m_(2)) = mu sin theta - cos theta`C. `(m_(1))/(m_(2)) gt ( sin theta + mu cos theta)`D. `(m_(1))/(m_(2)) gt (sin theta - mu cos theta)` |
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Answer» Correct Answer - C `m_(1)g gt (m_(2) g sin theta + mu_(2) g cos theta)` `(m_(1))/(m_(2)) gt ( sin theta + mu cos theta)` |
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