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Two balls of same mass are dropped from the same height h, on to the floor. The first ball bounces to a height h/4, after the collision `&` the second ball to a height h/16. The impulse applied by the first `&` second ball on the floor are `I_(1)` and `I_(2)` respectively. ThenA. `5I_(1)=6I_(2)`B. `6I_(1)=5I_(2)`C. `I_(1)=2I_(2)`D. `I_(2)=2I_(1)` |
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Answer» `(I_(2))/(I_(2))=(msqrt(2gh)+msqrt(2gh//4))/(msqrt(2gh)+msqrt(2gh//16))` `=(1(1)/(2))/(1+(1)/(4))=((3)/(2))/((3)/(4))=(6)/(5)` |
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