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Two balls of equal masses are thrown upwards along the same vertical direction at an interval of 2 second ,with same initial velocity of 45 m/s then find at what height balls will collide |
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Answer» t1= 45/10=4.5sec t2=2.5 at instant of 4.5 sec 1st ball lis at Hmax = and SECOND ball is at 81.25m so now the DISTANCE bw them is 60m and they are under GRAVITY so grelative= v at that instant =U-gt=45-25=20m/s h(distance between BALLS)= u(ball b with respect to ball a)*t 60=(ub+ua)*t 60=(20+0)+t t=3sec H=1/2g3² H= 45 m |
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