1.

Two balls of equal masses are thrown upwards along the same vertical direction at an interval of 2 second ,with same initial velocity of 45 m/s then find at what height balls will collide

Answer»

t1= 45/10=4.5sec t2=2.5

at instant of 4.5 sec 1st ball lis at Hmax =

and SECOND ball is at

81.25m

so now the DISTANCE bw them is 60m

and they are under GRAVITY so

grelative=

v at that instant =U-gt=45-25=20m/s

h(distance between BALLS)= u(ball b with respect to ball a)*t

60=(ub+ua)*t

60=(20+0)+t

t=3sec

H=1/2g3²

H= 45 m



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