Two balls are projected at an angle θ and (90° – θ) to the horizo

1.	Two balls are projected at an angle θ and (90° – θ) to the horizontal with the same speed. The ratio of their maximum vertical heights is(A) 1 : 1 (B) tan θ : 1 (C) 1 : tan θ (D) tan2 θ : 1
Answer» Correct Option is (D) \(tan^2 \theta : 1\) Maximum vertical height \(H = \frac{u^2 sin^2 \theta}{g}\) \(H_1 = \frac{u^2 sin^2 \theta}{g}\) \(H_2 = \frac{u^2 sin^2 (90 - \theta)}{g}\) .... \(\because \theta = (90 - \theta)\) \(\frac{H_1}{H_2} = \frac{Sin^2 \theta}{Cos^2 \theta}\) \(\frac{H_1}{H_2} = \frac{tan^2 \theta}{1}\) Correct option is: (D) tan² θ : 1

Two balls are projected at an angle θ and (90° – θ) to the horizontal with the same speed. The ratio of their maximum vertical heights is(A) 1 : 1 (B) tan θ : 1 (C) 1 : tan θ (D) tan2 θ : 1

Answer»

Correct Option is (D) \(tan^2 \theta : 1\)

Maximum vertical height \(H = \frac{u^2 sin^2 \theta}{g}\)

\(H_1 = \frac{u^2 sin^2 \theta}{g}\)

\(H_2 = \frac{u^2 sin^2 (90 - \theta)}{g}\) .... \(\because \theta = (90 - \theta)\)

\(\frac{H_1}{H_2} = \frac{Sin^2 \theta}{Cos^2 \theta}\)

\(\frac{H_1}{H_2} = \frac{tan^2 \theta}{1}\)

Correct option is: (D) tan² θ : 1