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Two angles of the triangles are given. Find the third angle.(i) 80°, 60°(ii) 52°, 68°(iii) 75°, 35°(iv) 50°, 90°(v) 120°, 30°(vi) 55°, 85° |
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Answer» (i) 80°, 60° Let the third angle be x. Sum of the angles = 180° 80° + 60° + x = 180° 140 + x = 180° x = 180°- 140° x = 40° Third angle = 40° (ii) 52°, 68° Let the third angle be x. Sum of the angles = 180° 52° + 68° + x = 180° 120 + x = 180° 180° – 120° x = 60° Third angle = 60° (iii) 75°, 35° Let the third angle be x. Sum of the angles 180° 75° + 35° + x = 180° 110 + x = 180° x = 180° – 110° x = 70° Third angle = 70° (iv) 50°, 90° Let the third angle be x. Sum of the angles = 180° 50° + 90° + x = 180° 140 + x = 180° x = 180° – 140° x = 40° Third angle = 40° (v) 120°, 30° Let the third angle be x. Sum of the angles = 180° 120° + 30° + x = 180° 150 + x = 180° x = 180° – 150° x = 30° Third angle = 30° (vi) 55°, 85° Let the third angle be x. Sum of the angles = 180° 55° + 85° + x = 180° 140 + x = 180° x = 180° – 140° x = 40° Third angle = 40° |
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