1.

Two adjacent sides of a rectangle are3a - b and 6b - a then its perimeter is

Answer»

Perimeter of rectangle = 2(l+b)Taking 3a-b =l and 6b-a=bPerimeter= 2(3a-b+6b-a)= 2(2a+5b)= 4a+10b

2(3a-b+6b-a) 2(2a+5b)4a+10b



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