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Two 50 mu F capacitors connected in parallel are charged by using a 12.0V battery.As soon as the battery is removed then an insulator of dielectic constant kappa=5.0 is inserted to the filling spaces between these capacitors. Calculate the energy stored in the capacitor system after insertion of insulators between two capacitors. |
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Answer» hat,Capacitors = 50 μFPotential difference = 12.0 VWe need to calculate the net capacitorsUsing formula of parallelPut the value into the formulaWe need to calculate the chargeUsing formula of potential differencePut the value into the formulaWe need to calculate the energy STORED in the capacitor systemUsing formula of energyPut the value into the formulaThe capacitance increases as the dielectric constant K>1The capacitance increases then the energy will decrease.Hence, The energy stored in the capacitor system after INSERTION of insulators between two capacitors is 7.2 MJ. |
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