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Tungsten crystallizes in body centred cubic unit cell. If the edge of the unit cell is 316.5 pm, what is the radius of Tungsten atom ? |
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Answer» SOLUTION :For BCC unit CELL `r = (sqrt(3)a)/(4)` `r = (sqrt(3) XX "316.5 pm")/(4)` `r = (1.732 xx "316.5 pm")/(4)` r = 137 pm |
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