1.

Tumua s grauupartis(xi) A teacher is 18 years elder to her student.3 years ago one-tenth of the teacher's age wasequal to one-fourth of the student's age. Findtheir present ages.​

Answer»

let student age be x

then teacher's age = (x +18)

Three YEARS ago

student age = x-3

teacher's age = x+18-3

BY THE QUESTION

1/10× x+18-3 =1/4× x-3

x+15/10 = x-3/4

(x+15)×4=10(x-3) [CROSS multiply]

4x+60=10x-4x

90=6x

x=90

6

=15

so student = 15yrs (ANS)

teacher = 15+18 = 33yrs (ANS)



Discussion

No Comment Found

Related InterviewSolutions