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Tumua s grauupartis(xi) A teacher is 18 years elder to her student.3 years ago one-tenth of the teacher's age wasequal to one-fourth of the student's age. Findtheir present ages. |
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Answer» let student age be x then teacher's age = (x +18) Three YEARS ago student age = x-3 teacher's age = x+18-3 BY THE QUESTION 1/10× x+18-3 =1/4× x-3 x+15/10 = x-3/4 (x+15)×4=10(x-3) [CROSS multiply] 4x+60=10x-4x 90=6x x=90 6 =15 so student = 15yrs (ANS) teacher = 15+18 = 33yrs (ANS) |
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