Saved Bookmarks
| 1. |
TU20. Sum of n terms of the series V2 + 8 + V18 + 32 + ...is11 (11+1)n(n+1)(6) 2n (n + 1) (c) 5(a(d) 1 |
|
Answer» a1=√2,a2=√8= 2√2a3=√18=3√2a4=√32=4√2_________________________________common difference a2-a1= 2√2-√2=√2so d=√2hence Sn=n/2(2a+(n-1)d)=n/2(2*√2+(n-1)*√2))=n/2(2√2+√2n-√2)=n/2(√2+√2n)=n(n+1)/√2 |
|