1.

टिका 1 डा 8 +९०४0 sin - cos 0sin—cos sin+cos

Answer»

Let theta = a

LHS:(sina+cosa)/(sina-cosa)+(sina-cosa)/(sina+cosa)=((Sina+cosa)^2)+((sina-cosa)^2)/((sina-cosa)(sina+cosa))=(Sin^2a+cos^2a+2sinacosa+sin^2a+cos^2a-2sinacosa)/(sin^2a-cos^2a)=2(sin^2a+cos^2a)/(sin^2a -cos^2a )=2/(sin^2a -cos^2a )Multiply and Divide by cos^2a=2sec^2a/tan^2a - 1= RHSHence proved



Discussion

No Comment Found