Hey FRIEND Here is your answerlet theta=¢x= acos¢a/x= 1/cos¢a/x= sec¢ ------(i)y= bcot¢b/y =1/cot¢b/y = tan -------(ii)squaring EQ i and ii and SUBTRACTING eq ii from eq i , we GET a^2/x^2 - b^2/y^2= sec^2¢ - tan^2¢a^2/x^2 - b^2/y^2= 1 Proved__________________________Hope it is useful
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