त्रिभुज ABC में अंत : कोण , कोण

1.	त्रिभुज ABC में अंत : कोण , कोण B तथा कोण C के समद्विभाजक 0 बिन्दु पर मिलते हैं । यदि कोण A = 50° और कोण B = 70° तो कोण BOC ज्ञात करें ।
Answer» SUM of TRIANGLE=180°. so, triangle(BOC)=180°-50°+70°=180-120. =180-120=60. so,triangle(boc)=60° ANS.

त्रिभुज ABC में अंत : कोण , कोण B तथा कोण C के समद्विभाजक 0 बिन्दु पर मिलते हैं । यदि कोण A = 50° और कोण B = 70° तो कोण BOC ज्ञात करें ।

Answer»

SUM of TRIANGLE=180°.

so, triangle(BOC)=180°-50°+70°=180-120.

=180-120=60.

so,triangle(boc)=60° ANS.

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