1.

Triangle MNO is a right-angled triangle. Its legs are 6 cm and8 cm long. Length of perpendicular NP on the side MO isa 4.8cmb 3.6 cmc 2.4 cmd 1.2 cm​

Answer»

Answer:

a 4.8cm

Step-by-step explanation:

by PYTHAGORAS theorem

length of SIDE MO

MO²= MN²+ NO²

MO²= 8²+6²

MO²= 64+36

MO²=100

MO= 10 cm

area of the triangle MNO

(MN×NO)/2

(8×6)/2 =

48/2 =

24cm²

area of the triangle MNO

(NP×MO)/2

24cm² = (NP×10)/2

48 = (NP×10)

48/10 = NP

4.8cm = NP



Discussion

No Comment Found

Related InterviewSolutions