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triangle in 3 cm, find the length of the corresponding side of the larger triangle.triangle in 40 cm, find the area of the larger triangle.CD 12 cm and PS 36 cm, then determine PQ. QRand RS.19. Corresponding sides of two similar triangles are in the ratio 1:3. If the area of the small20. In Fig. 4.232,each of PA, QB, RC and SD is perpendicular to l. If AB- 6 cm, BC-9 cPQR SAB CDFig. 4.232

Answer»

Area 1/area 2 = (length 1/length 2)²

40/area 2 = (1a/3a)²

area 2 = 40 / (1/3)²

= 40 * 3²

= 360

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