triangle, if its perimeter is 55 m.7 Divide 34 into two parts in such

1.	triangle, if its perimeter is 55 m.7 Divide 34 into two parts in such a way that four-seventh of one part is equal to two-fifth of the other.ins nd some 50-paise coins. The total amount in the bag is 25. If the
Answer» Let two parts of number are x and (34 - x) As per given condition(4/7)x = (2/5)(34 - x)4x/7 = 68/5 - 2x/54x/7 + 2x/5 = 68/5(20x + 14x)/35 = 68/534x/35 = 68/5x = 6835/345x = 2*7 = 14 Therefore two parts of number are 14 and 20

triangle, if its perimeter is 55 m.7 Divide 34 into two parts in such a way that four-seventh of one part is equal to two-fifth of the other.ins nd some 50-paise coins. The total amount in the bag is 25. If the

Answer»

Let two parts of number are x and (34 - x)

As per given condition(4/7)x = (2/5)(34 - x)4x/7 = 68/5 - 2x/54x/7 + 2x/5 = 68/5(20x + 14x)/35 = 68/534x/35 = 68/5x = 68*35/34*5x = 2*7 = 14

Therefore two parts of number are 14 and 20