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Triangle ABCABCA, B, C has the following vertices: A(-4,6)A(−4,6)A, left parenthesis, minus, 4, comma, 6, right parenthesis B(6,6)B(6,6)B, left parenthesis, 6, comma, 6, right parenthesis C(1,-3)C(1,−3)C, left parenthesis, 1, comma, minus, 3, right parenthesis Is triangle ABCABCA, B, C an equilateral triangle, and why |
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Answer» Answer: distance between A and B=√(6+4)^2+(6-6)^2 =10 distance between B and C=√(1-6)^2+(-3-6)^2 =√25+81 =√106 AB is not EQUAL to BC ABC is not EQUILATERAL TRIANGLE |
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