1.

Triangle ABC is right-angled at A and AD is perpendicular to BC.If AC=12 cm and BC = 13cm.Find the area and also find the length of altitude AD​

Answer»

Step-by-step explanation:

CONSIDER a TRIANGLE ABC where A=90°

Now,AC=12

BC=13(hypotenuse)

Now, by Pythagoras theorem,

BC^2 - AC^2=AB^2

169-144=25

AB^2 =25

AB=5

I HOPE YOU UNDERSTAND.

NOW AD is altitude, and BC is a Base.

DRAW a figure, if you have any doubts.

Area of triangle = 1/2 base x height

30=1/2 x 13 X height

Height(AD) =60/13


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