Travelling with a constant acceleration, a body travels a distance of 36 m in the 6th second and a distance of 48 m in the gth second. Find the speed at the end of 7th second.

Travelling with a constant acceleration, a body travels a distance of

1.	Travelling with a constant acceleration, a body travels a distance of 36 m in the 6th second and a distance of 48 m in the gth second. Find the speed at the end of 7th second.
Answer» =12 at n=5s ⟹12=u+ 2 9a a=4m/s 2 and u=−6m/s Now we have to FIND velocity at t=5s we KNOW that v=u+at ⟹v=−6+(4×5)=14m/s now distance travelled in next 3s can be CALCULATED by S=ut+ 2 1 at 2 Note: now u=14m/s ⟹S=14×3+ 2 1 4(3 2 )=60m

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Travelling with a constant acceleration, a body travels a distance of 36 m in the 6th second and a distance of 48 m in the gth second. Find the speed at the end of 7th second.​

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Travelling with a constant acceleration, a body travels a distance of 36 m in the 6th second and a distance of 48 m in the gth second. Find the speed at the end of 7th second.