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Travelling at 80 kmph a person can reach his destination in a certain time. He covers 3 /4 of the journey in 4/ 5 of the total time. At what speed should he travel the remaining distance to reach his destination on time? |
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Answer» ong>Answer: 100 km/h Step-by-step explanation: We can solve this in two ways, I will show you both ways, so here we GO......... Method 1 Let the Total Distance for the Journey be 'D' km and Total Time be 'T' hrs Thus, D/T = 80 km/h ---- 1 Now, According to the Question, He travelled 3/4 of the distance in 4/5 of time That is, (3/4)D in (4/5)T Now, distance left = D - (3/4)D = (4/4)D - (3/4)D = (1/4)D and time left = T - (4/5)T = (5/5)T - (4/5)T = (1/5)T Thus, we need to find the speed required to travel (1/4)D in (1/5)T Speed = Distance/Time = (1/4)D ÷ (1/5)T = D/4 × 5/T = 5/4(D/T) From eq.1 we get D/T = 80 km/h Speed = (5/4) × (80) Speed = 100 km/h Thus, he must travel with a speed of 100 km/h to reach his destination on time. Method 2 We know that, Total Distance covered ÷ Total time taken = 80km/h Let the certain time mentioned here be 'x' hrs Speed = Distance/Time then, Distance = Speed × Time Distance = 80 × x = 80x km Now, He covers 3/4 of the distance in 4/5 of the time so, Distance covered = 80x × (3/4) = 60X km and the time taken = x × (4/5) = (4/5)x Now the distance left = 80x - 60x = 20x km So, he has 20x km more to finish his journey Time left = x - (4/5)x = (5/5)x - (4/5)x = (1/5)x So, he has (1/5)x more to finish his journey Now, He has to complete 20x km in (1/5)x hrs then, Speed = 20x/(1/5)x = 20x ÷ (1/5)x = 20x × (5/x) = 20 × 5 = 100 km/h Thus, he must move with a speed of 100 km/h to reach the destination on time. Hope it helped and you UNDERSTOOD it........All the best |
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