train starting from rest attains velocity of 108km/h in 20 min. find t

1.	train starting from rest attains velocity of 108km/h in 20 min. find the acceleration and distance travelled by the train for attaining this velocity assuming the acceleration to be uniform
Answer» Answer: Acceleration = 324 km/hr^2 Distance TRAVELLED = 18 km Explanation: given:- U = 0 (INITIAL velocity) ,v = 108km/hr (final velocity) and ,t = 20min. = (1/3)hr. (time TAKEN) So, by applying v = u + a x t where, a = acceleration => 108 = 0 + a x (1/3) => a = 108 x 3 => a = 324 km/hr^2 Now, by applying S = u x t + (1/2) x a x t^2 where , S = distance travelled => S = 0 + (1/2) x 324 x (1/3)^2 => S = 324/18 => S = 18 km ....

train starting from rest attains velocity of 108km/h in 20 min. find the acceleration and distance travelled by the train for attaining this velocity assuming the acceleration to be uniform

Answer»

Answer:

Acceleration = 324 km/hr^2

Distance TRAVELLED = 18 km

Explanation:

given:- U = 0 (INITIAL velocity)

,v = 108km/hr (final velocity)

and ,t = 20min. = (1/3)hr. (time TAKEN)

So, by applying v = u + a x t

where, a = acceleration

=> 108 = 0 + a x (1/3)

=> a = 108 x 3

=> a = 324 km/hr^2

Now, by applying

S = u x t + (1/2) x a x t^2

where , S = distance travelled

=> S = 0 + (1/2) x 324 x (1/3)^2

=> S = 324/18

=> S = 18 km ....

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train starting from rest attains velocity of 108km/h in 20 min. find the acceleration and distance travelled by the train for attaining this velocity assuming the acceleration to be uniform​

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train starting from rest attains velocity of 108km/h in 20 min. find the acceleration and distance travelled by the train for attaining this velocity assuming the acceleration to be uniform