1.

TP and TQ are tangents rlto a circle with centre O, touches the circle at P and Q. if angle POQ 110° then find angle PTQ​

Answer» ONG>Answer:

GIVEN, ∠POQ=110

∘

We know,

∠OPT=∠OQT=90

∘

(Angle between the TANGENT and the radial line at the POINT of intersection of the tangent at the CIRCLE)

Now, in quadrilateral POQT

Sum of angles=360

∠OPT+∠OQT+∠PTQ+∠POQ=360

∘

90+90+∠PTQ+110=360

∠PTQ=360−290

∠PTQ=70

∘


Discussion

No Comment Found

Related InterviewSolutions