Total number of voids in 0.45 mol of a compound forming a hexagonal cl – InterviewSolution

1.	Total number of voids in 0.45 mol of a compound forming a hexagonal close packed structure is_______ ×1023. (Round off to the nearest integer)
Answer» Total number of voids in $0.45 m o l$ of a compound forming a hexagonal close packed structure is_______ $\times 10^{23} .$ (Round off to the nearest integer)

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