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Total number of atoms present in 23 g of NaNO2 is:Given: Atomic mass: Na=23 u,N=14 u,O=16 uNA=6.023×1023

Answer»

Total number of atoms present in 23 g of NaNO2 is:

Given: Atomic mass: Na=23 u,N=14 u,O=16 uNA=6.023×1023



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