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To verify that of all exterior angle of any polygon will be always 360 degree do in maths practical |
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Answer»
GIVEN: A polygon with ‘N’ number of sides , <1,<2,<3,<4,<5,…… TO PROVE: <1 + <2 + <3 + <4 + <5 + …… The sum of interior angles of any polygon =(n-2)*180 ………(FORMULA used) PROOF: <1 + <2 + <3 + <4 + < D = 180° ………..(4) <5 + And so on up to n times.. By adding all above (1)+(2)+(3)+(4)+(5)+….(n) <1+<2+<3+<4+<5+……. = 180n -{ ( n-2)*180 } = 180n - 180n + 2*180 = 2*180 = 360° => <1+<2+<3+<4+<5+….. [ HENCE PROVED] |
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