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To prove: Area of triangle ∆ADE: area of triangle ∆ABC = 3:4 |
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Answer» in tri ADE and tri ABC ag A = ag A(common ) AB = AD Aad = AC ( both are opp. sides ate equal ) by SAS pr. TR ADE ~trABC therefore , tr ADE :tr ABC 3^2/4^2 9/16 therefore , trADE : Tr ABC =9: 16 I hope this is clear too you if you understand plzz PUT in brainy list |
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