hemical equation          Molecular equations                          2 KMnO₄ + 3 H₂SO₄ ------> K₂SO₄ + 3 H₂O + 5[O]2 FeSO₄ (NH₄)₂SO₄.6H₂O + H₂SO₄ + [O] ----> Fe₂(SO₄)₂ + 2(NH₄)₂SO₄ + 13H₂O] × 5------------------------------------------------------------------------------------------------------------  2 KMnO₄ + 8H₂SO₄ + 10FeSO₄.SO₄.6H₂O ----->                                 K₂SO₄ + 2MnSO₄ + 5Fe₂(SO₄)₃ + 10(NH₄)₂ SO₄ + 68H₂O------------------------------------------------------------------------------------------------------------IONIC EQUATIONS             MnO₄⁻ + 8H⁺ + 5e¹ ------> Mn²⁺ + 4H₂O                                       Fe²⁺ -------> Fe³⁺ + e⁻¹] × 5         -----------------------------------------------------------------------          MnO₄⁻ + 8H⁺ + Fe²⁺ --------> Fe³⁺ + Mn²⁺ + 4H₂O         ----------------------------------------------------------------------Indicator   KMnO₄ is a self-indicatorEnd Point   Colourless to permanent PINK colour (KMnO₄ in burette)ProcedurePrepare 250 ml of M/20 Mohr's salt solution by dissolving 4.9 g of Mohr's salt in water. Rinse the PIPETTE with the M/20 Mohr's salt solution and pipette out 20.0 ml of it in a washed titration flask.Rinse and fill the burette with the given KMnO₄ solution.Add one test-tube ( 20 ml ) full of dilute sulphuric acid ( 2 M ) to the solution in titration flask.Note the initial reading of the burette.Now add KMnO₄ solution from the burette till a permanent light pink colour is IMPARTED to the solution in the titration flask on addition of last single drop of KMnO₄ solution.Note the final reading of the burette.Repeat the above steps 4-5 times to get a set of three concordant readings.Observation   Weight of watch glass  =   50.498 g   Weight of watch glass + Mohr's salt =  4.9 g   Weight of Mohr's salt = 4.90 g   Volume of Mohr's salt solution prepared = 250 ml   Molarity of Mohr's salt solution = M/20   Volume of Mohr's salt solution TAKEN for each titration = 20.0 mlS.No = 1Initial reading of the burette = 2.00 mlFinal reading of the burette = 19.50 mlS.No = 2Initial reading of the burette = 2.14Final reading of the burette = 19.45S.No = 3Initial reading of the burette = 2.25Final reading of the burette = 19.67S.No = 4Initial reading of the burette = 2.91Final reading of the burette = 20.1NOTE :- I have performed this experiment so according to that i have given the values.Concordant volume = x mlCalculations(a) Molarity of the KMnO₄ solution From the overall balanced chemical equation, it is clear that 2 moles of KMnO₄ reacts with 10 moles of Mohr's salt∴ MkMno₄ × VKMnO₄ / M mohr's salt × V Mohr's salt = where,                M KMno₄ = Molarity of KMnO₄ solution               V KMnO₄ = Volume of KMnO₄ solution               M Mohr's salt = Molarity of Mohr's salt solution              V Mohr's salt = Volume of Mohr's salt solution M KMnO₄ × x / 1 / 20 × 20 = 2/10               M KMnO₄ = 2/10 × 1/x = 2/10 x(b) Strength of the KMnO₄ solution            Molar mass of KMnO₄ = 158 g mol⁻¹Strength (in g/L)  = Molarity × Molar mass = 2/10x × 158 gL⁻¹GOOD LUCK !!