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To prepare a buffer solution of pH=4.04, amount of Barium acetate to be added to 100 mL of 0.1 M acetic acid solution `[pK_b(CH_(3)COO^(-))=9.26]` is:A. 0.05 moleB. 0.025 moleC. 0.1 moleD. 0.005 mole |
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Answer» Correct Answer - B For the buffer solution of `CH_3COOH & CH_3COO^(-)` `pH=pK_a + "log" ([CH_3COOH])/([CH_3COO^(-)])" " implies 4.04=4.74+"log" ((100xx0.1))/(m."moles of " CH_3COO^(-))` `implies` m.moles of `CH_3COO^(-)=50 " " therefore` moles of `(CH_3COO)_2` Ba required =0.025. |
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