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To do so small sample equal to 1 gauge identical to catch a pleasant contact unofficial as far as rental service support of 10 to 10 is acting remember what is the Florissant Road Elgin and banana to |
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Answer» The spring constant of spring K=100N/mThe length of the spring is l=10cm=10 −1 mThe MAGNITUDE of CHARGE is q=2.0×10 −8 CFind the extension in the spring x ′ =?FORCE between the charge particles is :F= R 2 kq 1 q 2 = 10 −2 9×10 9 ×2×10 −8 ×2×10 −8 =36×10 −5 NThis electrostatic force is same as the force exerted on the spring. So,So, F=−kx or x= −kF = 10036×10 −5 =36×10 −7 cm=3.6×10 −6 m. |
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