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Time taken by a 836 W heater to heat one litre of water from `10^@C to 40^@C` isA. 150 sB. 100 sC. 50 sD. 200 s |
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Answer» Correct Answer - A (a) `DeltaQ = mC xx DeltaT` `= 1 xx 4180 xx (40-10) = 4180 xx 30 ` `(:. DeltaQ = heat supplied in time t for heating 1L water from `10^@C to 40^@C`) `also Delta Q = 836 xx t rArr t = (4180 xx 30)/836 = 150 s.` |
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