1.

Time taken by a 836 W heater to heat one litre of water from `10^@C to 40^@C` isA. 150 sB. 100 sC. 50 sD. 200 s

Answer» Correct Answer - A
(a) `DeltaQ = mC xx DeltaT`
`= 1 xx 4180 xx (40-10) = 4180 xx 30 `
`(:. DeltaQ = heat supplied in time t for heating 1L water
from `10^@C to 40^@C`)
`also Delta Q = 836 xx t rArr t = (4180 xx 30)/836 = 150 s.`


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