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Time taken by a 836 W heater to heat one litre of water from `10^@C to 40^@C` isA. `50s`B. `100s`C. `150s`D. `200s`

Answer» Correct Answer - C
Let time taken in boiling the water by the heater is `t` sec. then
`Q=ms DeltaTimplies(Pt)/J=msDeltaT`
`836/4.2t=1xx1000(40^(@)-10^(@))`
`836/4.2t=1000xx30`
`t=(1000xx30xx4.2)/836`
`=150 ` second


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