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Time taken by a 836 W heater to heat one litre of water from `10^@C to 40^@C` isA. `50s`B. `100s`C. `150s`D. `200s` |
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Answer» Correct Answer - C Let time taken in boiling the water by the heater is `t` sec. then `Q=ms DeltaTimplies(Pt)/J=msDeltaT` `836/4.2t=1xx1000(40^(@)-10^(@))` `836/4.2t=1000xx30` `t=(1000xx30xx4.2)/836` `=150 ` second |
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