Time period of simple pendulum is measured to be T = (2.5 ± 0.1) s, t

1.	Time period of simple pendulum is measured to be T = (2.5 ± 0.1) s, then percentage error in measurement is a) 2% b) 4% c) 1% d) 2.5%
Answer» Correct option is b) 4% Given T = (2.5 \(\pm\) 0.1) Then T = 2.5, ΔT = 0.1 So Percentage error = \(\frac{\Delta T}T \times 100\) \(= \frac{0.1}{2.5} \times 100\) \(= \frac{100}{25}\) \(= 4\)%

Time period of simple pendulum is measured to be T = (2.5 ± 0.1) s, then percentage error in measurement is a) 2% b) 4% c) 1% d) 2.5%

Answer»

Correct option is b) 4%

Given

T = (2.5 \(\pm\) 0.1)

Then T = 2.5, ΔT = 0.1

Percentage error = \(\frac{\Delta T}T \times 100\)

\(= \frac{0.1}{2.5} \times 100\)

\(= \frac{100}{25}\)

\(= 4\)%

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Time period of simple pendulum is measured to be T = (2.5 ± 0.1) s, then percentage error in measurement is a) 2% b) 4% c) 1% d) 2.5%

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