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Time for 20 oscillations of pendulum is measured as t1 = 39.6 s; t2 = 39.9 s; t3=39.5 s. What is the precision in the measurements? What is the accuracy of the measurement? |
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Answer» (a) Precision is given by the least count of the instrument. For 20 oscillations, precision = 0.1 s For 1 oscillation, precision = 0.005 s. Average time for 20 oscillations \(t=\frac{39.6+39.9+39.5}{3}s=39.7sec\) Absolute errors, ∆t1 = t − t1 = 39.7 – 39.6 = 0.1 s. ∆t2 = t − t2 = 39.7 – 39.9 = −0.2s ∆t3 = t − t3 = 39.7 – 39.5 = 0.2s Mean absolute error, \(=\frac{|Δt_1|+|Δt_2|+|Δt_3|}{3}\) \(=\frac{0.1+0.2+0.3}{3}\)=\(\frac{0.5}{3}\) = 0.17 ≈ ±0.2s. |
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