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Thu Aunvio la calutat u est and S tav abuu |
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Answer» First term =a second term =blast term =ccommon difference=(b-a)tn =a+(n-1) d c=a+(n-1) d (c-a)=(n-1)(b-a) (c-a)/(b-a)+1=n ( c+b-2a)/(b-a)=n--------------------(1)now ,we know sum of n terms=n/2 (first term+last term)put equation (1)value = (b+c-2a)/(b-a)(a+c)hence Sn=[(b+c-2a)(c+a)/(b-a)] |
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