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Three vertices of a square are p (-1,-9), Q (3,-1), R(-5,3). Find the coordinates of vertex S. |
Answer» Mid Point Formula→ (x₁+ x₂)/2 , (y₁ + y₂)/2 = (Coordinate of mid point) → (- 1 - 5)/2, (- 9 + 3)/2 = LHS → - 3, - 3 = LHS → (3 + x)/2, (- 1 + y)/2 = RHS Since, in a SQUARE diagnonals are EQUAL and bisect each other. → (3 + x)/2, (-1 + y)/2 = - 3, - 3 → (3 + x)/2 = - 3 and (-1 + y)/2 = - 3 → 3 + x = - 6 and - 1 + y = - 6 → x = - 9 and y = - 5 Hence, Coordinate of VERTEX S is - 9, - 5. Answer : (- 9, - 5) |
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