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Three vertices of a square are given. If the fourth vertex is (2, P) find the ratio of P. Find the area of the square. |
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Answer» Distance between (-6, 8) and (2, P) = \(\sqrt{(-6-2)^2+(8-P)^2}\) They are equal 82 + (8 - P)2 = 62 + (6 - P)2 64 + 64 - 16P + P2 = 36 + 36 - 12P + P2 4P = 56 \(P=\frac{56}{4}=14\) Distance between (0,0) and (8,6) = \(\sqrt{8^2-6^2}=10\) Area = 102 = 100 |
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