1.

Three vertices of a square are given. If the fourth vertex is (2, P) find the ratio of P. Find the area of the square.

Answer»

Distance between (-6, 8) and (2, P)

\(\sqrt{(-6-2)^2+(8-P)^2}\)

They are equal

82 + (8 - P)2 = 62 + (6 - P)2

64 + 64 - 16P + P2

= 36 + 36 - 12P + P2

4P = 56

\(P=\frac{56}{4}=14\)

Distance between (0,0) and (8,6)

\(\sqrt{8^2-6^2}=10\)

Area = 102 = 100



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