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Three uniform spheres each having mass 'm' and radius 'r are kept in such a way that each touches the other. The magnitudeof the gravitational force on any sphere due to the other two is |
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Answer» Solution :Let `F_(1) = F_(2) = F` here `F = (Gm.m.)/((2R)^(2)) = (Gm^(2))/(4R^(2))` `therefore` The resultant gravitational FORCE `F_(R) = 2F COS theta//2` `F_(R)= 2F cos 30^(@) = sqrt(3)F = sqrt(3)(Gm^(2))/((2R)^(2)) = sqrt(3)(Gm^(2))/(4R^(2))`
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