1.

Three times of a number added to two times of another number gives 33. When three times of the second number is subtracted from four times the other number got 10. taking the numbers as x and y form the equations and find the numbers?

Answer»

n :

  • Three TIMES of a NUMBER added to two times of another number gives 33.
  • Three times of second number subtracted from four times the first number gives 10.

To find :

  • Two numbers

Solution

Let the numbers be x and y

A/q to 1st condition,

⇒ 3x + 2Y = 33                           __(i)

A/q to 2nd condition,

⇒ 4x - 3y = 10                            __(II)

Now multiplying (i) into 3 and (ii) into 2, we get,

                         9x + 6y = 99

                         8x - 6y  = 20

                      (+)__(-)___(+)_

                          17x = 119

                        ⇒ x = 119/17

                        ⇒ x = 7

Now putting value of x in (i) :

⇒ 3(7) + 2y = 33

⇒ 21 + 2y = 33

⇒ 2y = 33 - 21

⇒ 2y = 12

⇒ y = 12/2

⇒ y = 6

Therefore,

First number is 7 and second number is 6 .


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