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Three tankers contain 385litre 415litre and 505litre of petrol respectively. Find the minimum capacity of a container that can measure the petrol of the three tankers exact number of times.Give the answer in full explination if you don't give the answer in the full explination your answer is not submitted to me if you give the answer i Mark you as Brainliest |
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Answer» Min. capacity of REQUIRED CONTAINER=HCF(385,415,505) 385 = 5×7×11 415 = 5×83 505 = 5×101 HCF = 5 .°. Required container = 5L. |
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